Find three consecutive odd integers such that six times the sum of the first and second is 5 less than 11 times the third

Question

Find three consecutive odd integers such that six times the sum of the first and second is 5 less than 11 times the third

Answer 1

6f+6s=11t-5

6x-12+6x =11x+22-5

x= 29

27,29,31 are the numbers

6(27+29)=11(31)-5

6(56)= 341-5

336=336