Both of the expressions are differences of squares. So they are equal to
1)(a-b+c-d)(a-b-c+d)
2)(a-b+c+d)(a-b-c-d).
Rachel F.
asked 07/24/23(a - b)^2 - (c - d)^2 and factorise fully
(a - b)^2 - (c + d)^2
Both of the expressions are differences of squares. So they are equal to
1)(a-b+c-d)(a-b-c+d)
2)(a-b+c+d)(a-b-c-d).
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Rachel F.
Thanks - working out please.07/24/23