
Lily F.
asked 07/11/23what is the integral of this function
73x+1*x2-(x+1)/x+4
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1 Expert Answer
David G. answered 07/11/23
Tutor
New to Wyzant
Mathematics and Statistics Tutor
73x+1*x2-1-1/x+4
The first part can be integrated by parts (twice)
∫x273x+1dx = |u=x2, du=2xdx, dv=73x+1dx, v=(1/ln(7))73x+1| =
=(x273x+1)/ln7- 2/ln7∫x73x+1dx = again integrate by parts and you are done. The rest is elementary. Hope this helps
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Kevin S.
07/12/23