Inactive Tutor answered 06/26/23
Tutor
New to Wyzant
dy = y'dx = 3sec2(3x + 6)dx = 3sec2(18)·0.1 = 0.688;
dy = y'dx = 3sec2(3x + 6)dx = 3sec2(18)·0.2 = 1.3761.
Inactive Tutor answered 06/26/23
dy = y'dx = 3sec2(3x + 6)dx = 3sec2(18)·0.1 = 0.688;
dy = y'dx = 3sec2(3x + 6)dx = 3sec2(18)·0.2 = 1.3761.
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