The boundary curve C of σ is the circle x2 + y2 = 9 in the xy-plane z = 0. By Stokes's theorem, your integral equals the line integral ∫C F • dr. Since z = 0 on C, F • dr = x dy on C. So
∫C F • dr = ∫C x dy = Area(C) = π(32) = 9π.
Elena G.
asked 06/20/23If F (x,y,z)=tan z i +(x+z)j+xsiny k and σ is the portion of the cylinder z=9-x2-y2 above the xy-plane oriented so that the unit normal vector n points to the outside of the cylinder, use Stoke's theorem to evaluate ∫∫σ(∇ x F) • n dS.
The boundary curve C of σ is the circle x2 + y2 = 9 in the xy-plane z = 0. By Stokes's theorem, your integral equals the line integral ∫C F • dr. Since z = 0 on C, F • dr = x dy on C. So
∫C F • dr = ∫C x dy = Area(C) = π(32) = 9π.
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