
Dayv O. answered 06/08/23
Caring Super Enthusiastic Knowledgeable Pre-Calculus Tutor
ds=[√(x'2+y'2+z'2)]dt
ds=[√(4sin2t+4cos2t+π2)]dt
ds=[√(4+π2)]dt,,,,,which is a constant times dt
so I=√(4+π2)∫(2cos(t)+πt)dt ,,,t from 0 to π
I=√(4+π2)*[2sin(t)+πt2/2],,, t from 0 to π
I=√(4+π2)*π3/2
I≈57.7