solve for X

solve for X

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Since no method is suggested, and the format that the problem is written in sets it up to be used, I am going to solve with the
**Completing the Square** method.

3x^{2} + 12x = 3 Given

x^{2} + 4x = 1 Divide each term by 3 (the coefficient on the x^{2})

x^{2} + 4x + 4 = 1 + 4 Add 4 to each side (the coefficient on x, divided by 2 and squared)

(x + 2)^{2} = 5 Factor the left side/simplify the right side

x + 2 = +/-√5 Take the square root of each side

x = -2 +/-√5 Subtract 2 from each side

## Comments

Sorry I meant 3X^2+12X+3