passes through (-3,6) with a slope of -2

Question

math

Answer 1

Problem: What is the slope of the line that passes through (-3, 6) with a slope of -2?

Solution: Use the point-slope intercept form, which is: for a point (x₁, y₁), and equation y - y₁ = m(x - x₁)

let slope = m, where m = -2, and (x₁, y₁) = (-3, 6), inserting into the above equation gives us --

y - 6 = -2 * [x - (-3)] ≅ y - 6 = -2 * (x + 3) ≅ y - 6 = -2x - 6

then, adding 6 to both sides, y - 6 + 6 = -2x - 6 + 6 ≅ y = -2x.

y = -2x is an equation that passes through the origin, since (0,0) satisfies the equation.

Answer 2

Answer 3

Hi Jazlyne! I assume you're asking how to make an equation of a line that passes through (-3,6) with a slope of 2?

If that's the case, there are two possible answers.

Slope-Intercept form (y = mx + b)

y = 2x + b

In order to find b, you need to plug the point (-3,6) in for x and y in the equation using 2 as the slope.

6 = 2(-3) + b

6 = -6 + b

12 = b

so: y = 2x + 12

Point-slope form: y - y₁ = m(x - x₁)

This is the more simple method here, since you have everything you need. Plug your point in for the x₁ and y_1, and the slope for m.

So: y - 6 = 2(x + 3)