Determine which of the following points is a solution to the inequality

Question

y≤-(x+2)²+3

1. (0.-1)
2. (0,0)
3. (1,2)
4. (2,-5)

Answer 1

just plug in the x and y values

y < -(x+2)^2 +3

first point is (x,y) = (0,-1), with x=0, y=-1

-1 < -(0+2)^2+3 = -4+3 = -1

-1 = -1

so the 1st option (0,-1) is correct

check the other 3 if you want, but if the problem was designed to have just one solution, option 1 is it

(0,0) leads to 0 > -(0+2)^2+3 = -4+3 = -1, 0 is greater than -1

(1,2) leads to 2 > -(1+2)^2 +3 = -9+3 = -6, 2 is greater than -6

(2,-5) leads to -5 > -(2+2)^2 +3 = -16+3 = -13, -5 is greater than -13

only the 1st option works