given f(x)=x^3 -3 find the equation of the secant line passing through (-4, f(-4)) and (2, f(2))

Answer 1

f(-4)= -64-3=-67

f(2) = 8-3=5

line through (-4,-67) and (2,5) has slope =

(5+67)/2+4) = 72/6 = 12 = (y-5)/(x-2)

the secant line's equation is:

y = 12x-19