Geometry Math Problem

Question

Here is the link to the problem: https://docs.google.com/document/d/1sCT4LWlXsm3KGTRmOySjwvS4RiG5umGkpn7th7SlUF4/edit?usp=sharing

It includes the picture of the triangle, as well as the question and answer choices.

Answer 1

HI Alaska,

The problem can be solved using the "Side splitter theorem". If a line is parallel to one side of a triangle and intersects the other two sides, then it divides those sides proportionally.

In your diagram, BE and CD are parallel. So BE splits the sides of the triangle proportionally

AB = AE

BC ED

You are given AB=3, BC=8, DE=10.

3 = AE

8 10

(3)(10) = AE (8) [Cross-multiplied]

30/8 = AE

3.75 = AE

3.8 = AE rounded to the nearest tenth

Answer 2

Hi Alaska D

Choice e is the answer.

Your link did open to show a small triangle ABE with base BE inside a larger triangle ACD with base CD we are given:

BE parallel to CD

Side AB = 3

Side BC = 8

Side DE = 10

We are asked to find the length of side DE

You have similar triangles with parallel bases

(AB)/BC = (AE)/(DE)

3/8 = AE/10

(3)(10)/8 = DE

DE = 3.75 rounded per the list of choices 3.8

I hope this helps.