Joanne C. answered 05/17/23
Enthusiastic Math and Science Tutor with over 20+ years of experience
To solve this problem first you need to calculate the concentration of the H+ ion for each substance.
You will need to use the following log identity
y=logbx --> by=x
Lemon Juice
pH = −log[H+] Formula for PH
2 = - log[H+]lemon
-2 = log[H+]lemon This is log base 10
10(-2)= [H+]lemon
0.01 =[H+]lemon
Rain Water
pH = −log[H+] Formula for PH
6.5 = - log[H+]water
-6.5 = log[H+]water
10(-6.5)= [H+]water
3.16x10-7 =[H+]water
Now we can determine how many times more H+ concentration in the lemon juice compare with rain water
Lemon Juice [H+] ÷ Rain water [H+]
0.01 ÷ 3.16x10-7= 31646
Hope this helps