Let an = nth term of an arithmetic sequence
= a1 + (n-1)d, where a1 = first term and d = common difference
a3 = a1 + 2d = 59
a7 = a1 + 6d = 103
Subtract the equations to get -4d = -44. So, d = 11
a1 + 2d = a1 + 22 = 59
a1 = 37
Therefore, an = a1 + (n-1)d
a21 = 37 + (20)(11)
= 37 + 220 = 257