Moses O. answered 05/04/23
Maths and Physics Expert
a) To find the time it takes for the snowboarder to reach the exact bottom of the halfpipe, we need to find the value of t when h(t) = 0. The equation for the height of the snowboarder is:
h(t) = 0.1t^2 - 3.4t + 10
Setting h(t) = 0, we get:
0 = 0.1t^2 - 3.4t + 10
This is a quadratic equation that can be solved using the quadratic formula:
t = (-b ± sqrt(b^2 - 4ac)) / 2a
where a = 0.1, b = -3.4, and c = 10. Plugging in these values, we get:
t = (-(-3.4) ± sqrt((-3.4)^2 - 4(0.1)(10))) / 2(0.1) t = (3.4 ± sqrt(11.24)) / 0.2
Simplifying, we get:
t ≈ 7.47 seconds or t ≈ 2.53 seconds
The snowboarder reaches the exact bottom of the halfpipe twice during each jump - once on the way down and once on the way up. The first solution t ≈ 7.47 seconds is the time when the snowboarder reaches the bottom on the way down, while the second solution t ≈ 2.53 seconds is the time when the snowboarder reaches the bottom on the way up. Therefore, it will take the snowboarder 7.47 seconds to reach the exact bottom of the halfpipe.
b) To find how long his snowboard is touching the halfpipe between aerial tricks, we need to find the roots of the equation h(t) = 0. The time when the snowboarder takes off and lands will be when h(t) = 0, so the length of time his snowboard is touching the halfpipe is the time between these two roots.
Using the quadratic formula, we find the roots of the equation:
t = (-b ± sqrt(b^2 - 4ac)) / 2a
where a = 0.1, b = -3.4, and c = 10. Plugging in these values, we get:
t = (-(-3.4) ± sqrt((-3.4)^2 - 4(0.1)(10))) / 2(0.1) t = (3.4 ± sqrt(11.24)) / 0.2
Simplifying, we get:
t ≈ 7.47 seconds or t ≈ 2.53 seconds
Since the snowboarder takes off and lands at the bottom of the halfpipe, the length of time his snowboard is touching the halfpipe is the difference between these two roots:
t = 7.47 seconds - 2.53 seconds t ≈ 4.94 seconds
Therefore, the snowboarder's snowboard is touching the halfpipe for approximately 4.94 seconds between aerial tricks.