Factor: 5x^2-19x=-18

Question

There should be 2 different Xs. Please explain the steps

Answer 1

The first term in each of the factors must be 5x and x respectively since 5 is prime.

The sign in the middle of the 2 factors must be alike since the 18 is positive.

The possible factors of 18 are 18 & 1, 9 & 2 and 6 & 3.

You should see that 9 and 2 work: (5x-9)(x-2)

Answer 2

5x² - 19x = -18

5x² - 19x + 18 = 0

(5x - 9)(x - 2) = 0

5x - 9 = 0, can you solve for x and answer?

or

x - 2 = 0, can you solve for x and answer?

Answer 3

Step 1: 5x² - 19x + 18 = 0

Step 2: 18 x 5 = 90 ; 90 can be factorized by 9 x 10 and 9 + 10 = 19

Step 3: 5x² - 10x -9x + 18 = 0

Step 4: 5x(x - 2) -9(x - 2) = 0

Step 5: (x - 2)(5x - 9) = 0

Step 6: x - 2 = 0, 5x - 9 = 0

Step 7: x = 2, 9/5

Answer : x = 2, 9/5