
William W. answered 04/28/23
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Try simplification:
(-4x2)/2! = -2x2
(-13x3)/3! = (-13/6)x3
Owen H.
asked 04/27/23Write out the first four terms of the Maclaurin series of f(x) if:
f(0)=−11, f′(0)=8, f′′(0)=−4, f′′′(0)=−13
I get -11 + 8x + (-4x^2 / 2!) + (-13x^3 / 3!) but this is wrong apparently, why?
William W. answered 04/28/23
Top Pre-Calc Tutor
Try simplification:
(-4x2)/2! = -2x2
(-13x3)/3! = (-13/6)x3
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