There are 49 pennies, nickels, and quarters in a drawer. If their combined value is $2.41, and the number of pennies exceeds the number of nickels by 8, how many of each type are there?

Answer 1

p+n+q= 49

p +5n +25q = 241

p= n+8

n+8 + n +q= 49

2n +q = 41

q = 41-2n

n+8 + 5n + 25(41-2n) = 241

6n-50n = 241 -8 -25(41)

-44n = 233 -1025 = -792

n = 792/44 = 198/11 = 18 nickels

p = 18+8 = 26 pennies

q = 49-18-26 = 31-26 = 5 quarters

26 +5(18) +25(5)

= 26+90+125

= 116+ 125

= 241