when three halves of an integer squared subtracted from two-sevenths of the same integer squared is - 238 . Find the integer

Answer 1

2x/7 - (3x/2)^2 = -238

2x/7 - 9x^2/4 =-238

multiply by 28, the LCD to eliminate fractions

8x - 63x^2 = -238(28) =-6664

63x^2 -8x -6664 = 0

solve for x, factor, or use the quadratic formula. 2 possible answers, 1 positive real, & 1 negative real

using Descartes rule of signs

x = 8/126 +/- (1/126)sqr(64+4(63)(6664))

simplify

x = about 4/63 +/-(1/126)1295.91

= about 1303.91/2 or -1287.91/2

= about 651.955 or - 643.955

or maybe you meant

2x/7 - 3x^2/2 = -238

multiply by LCD = 14

4x -21x^2 =-238(14)

21x^2 -4x - 238(14) = 0

x = 4/42 +/-(1/42)sqr(16+84(238)(14))

x = (4 +/- 529.06)/42

x = about 533.06/42 or - 525.06/42

x = about 12.7 or - 12.5