Peter R. answered 04/21/23
Experienced Instructor in Prealgebra, Algebra I and II, SAT/ACT Math.
The area of the square plot is x times x or x2 sq ft.
The cost for the turf would be $15x2 and the cost for the sod would be $0.15x2.
Alia H.
asked 04/21/23Artificial turf costs $15/sq ft to install, and sod costs $0.15/sq ft to install.
Please explain everything
Peter R. answered 04/21/23
Experienced Instructor in Prealgebra, Algebra I and II, SAT/ACT Math.
The area of the square plot is x times x or x2 sq ft.
The cost for the turf would be $15x2 and the cost for the sod would be $0.15x2.
Raymond B. answered 04/21/23
Math, microeconomics or criminal justice
C(x) = 15.15x^2
t(x) = 15x^2 for turf cost
s(x) = .15x^2 for sod cost
C(x) = t(x)+s(x) = 15x^2 + .15x^2 = (15+.15)x^2 = 15.15x^2
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Alia H.
it's supposed to be 2 equations and how did you get that?04/21/23