Stephanie G. answered 04/21/23
Specializing in all MS and HS levels of Math - Prealgebra
Hello Ocean M., this math problem requires a multi-step solution. First, let's look at what information is given:
i. total is $113 for 1100 kwh plus an admin fee
ii. total is $153 for for 1500 kwh plus an admin fee
We are looking for the admin fee (not given)
Solution:
- Set up a linear equation for both usages
General structure: monthly electric bill is determined by adding a flat administration fee ( I call it F) to the product of the number of kilowatt hours of electricity used and the cost per kilowatt hour (I call it c)
Monthly Bill total = F + kwh*c
Now we can set this up for the specific scenario given in the problem set:
i. Monthly bill total = $113, 1100kwh*c , F = unknown
113 = F+1100c
ii. Monthly bill total = $153, 1500kwh*c , F = unknown
$153 = F+1500c
Note: we have 2 unknown variables in each equation (F and c). However, the admin fee is constant for each bill and never changes. Hence, we assume that F in equation one and equation 2 are the same value. We can solve both equations for F, set the equations equal to one another and solve for c:
i. 113 = F+1100c ii. 153 = F+1500c
-1100c -1100c -1500c -1500c
113-1100c = F 153-1500c = F
F=F , therefore
113-1100c = 153-1500c
Now solve for c
113-1100c = 153-1500c
+1500c +1500c
113+400c = 153
-113 -113
400c = 40
400c/400 =40/400
c= 1/10 = 0.1
So now, the cost has been determined to be $0.10. We can use any of the first original equations, plug the value of c we just found and solve for F. The value must be the same in both equations. I will show the solution for both:
i. $113 = F+1100c ii. $153 = F + 1500c
$113 = F+ 1100 ($0.10) $153 = F + 1500 ($0.10)
$113 = F+$110 $153 = F + $150
-$110 -$110 -$150 -$150
$3 = F $3 = F
What is the monthly administration fee? Answer: the monthly administration fee is $3.
Hope this helps.
-Stephanie G.