Since (0,4) is on the graph of y = a(b)x, 4 = a(b)0. So, a = 4
y = 4(b)x
Since (5,42) is also on the graph, we have 42 = 4(b)5. So, b5 = 10.5. b = (10.5)1/5.
Do the other problem in a similar manner.
Angeles L.
asked 04/19/23Find an approximate equation y=ab^x of the exponential curve that contains the given pair of points, round the value of b to two decimal places, show your work and write the full equation below.
(A) (0,4) and (5,42)
(B) (0,10) and (4,3,2)
Since (0,4) is on the graph of y = a(b)x, 4 = a(b)0. So, a = 4
y = 4(b)x
Since (5,42) is also on the graph, we have 42 = 4(b)5. So, b5 = 10.5. b = (10.5)1/5.
Do the other problem in a similar manner.
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