Steven G. answered 04/17/23
A=pir^2
dA/dt = 2pi*r*dr/dt
dA/dt(5) = 2* pi * 5 * 3 = 30pi
Zain L.
asked 04/17/23Steven G. answered 04/17/23
A=pir^2
dA/dt = 2pi*r*dr/dt
dA/dt(5) = 2* pi * 5 * 3 = 30pi
Raymond B. answered 04/17/23
A=pi(r^2)
if r=5
A = pi(5^2) = 25pi
=about 25(3.141593)
= about 78.54 = Area
or if, for some reason, you wanted to use calculus
find the area between the circle x^2 + y^2= 25 and the x axis
or find the area between the semi circle and the x axis
then multiply it by two
integrate to get the Area
dr/dt= r' = 5
A=pir^2
A' = 2pirr'
=2pi(3)(5) =30pi
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Steven G.
Did you read the question?04/17/23