h(t) = -4.9t2 + vt + h
h = 70 m
v (initial velocity) = 0
h(t) = 0 at ground level
0 = -4.9t2 + (0)t + 70
4.9t2 = 70
t2 = 14.28
t = 3.8 sec.
Patricia S.
asked 04/14/23Chuck drops a rock from a height of 70 m.
How long will it take the rock to hit the ground?
h (t) - -4.9t^2 + vt +h where v is the initial velociry and hi is the intial height.
Round to the nearest tenth of a second.
h(t) = -4.9t2 + vt + h
h = 70 m
v (initial velocity) = 0
h(t) = 0 at ground level
0 = -4.9t2 + (0)t + 70
4.9t2 = 70
t2 = 14.28
t = 3.8 sec.
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