Algebra 1 benchmark

Question

The area, in square units, of a rectangle is represented by 6x^3 - 2x^2+ 4x. If the width, in units, is 2x, what is the length, in units?

Enter the expression that represents the length, in units, in the box.

Answer 1

Area = length times width. Thus length = area / width → (length times width) / width

l = a / w = (6x³ -2x² +4x) / 2x

You can factor out 2x from the numerator(the area)

l = (2x) (3x² - x + 2) / 2x note the 2x in the numerator cancels with the 2x in the denominator

l = 3x² -x +2

Answer 2

Area = L x W, so Length is Area/Width

In this problem area is 6x³- 2x² + 4x and width is 2x.

So you'll need to divide to find the length. (6x³- 2x² + 4x)/2x. Use whatever method works best for you.