AJ L. answered 04/08/23
Patient and knowledgeable Calculus Tutor committed to student mastery
f(x,y) = 10x - x2 - 5xy2
∂f/∂x = 10 - 2x - 5y2 = 0
∂f/∂y = -10xy = 0
Notice that the bottom equation -10xy = 0 means that both x and y have to be 0, so this can be used to help solve for the top equation:
When x=0:
10 - 2x - 5y2 = 0
10 - 2(0) - 5y2 = 0
10 - 5y2 = 0
10 = 5y2
2 = y2
±√2 = y
(0,√2) and (0,-√2)
When y=0:
10 - 2x - 5y2 = 0
10 - 2x - 5(0)2 = 0
10 - 2x = 0
10 = 2x
5 = x
(5,0)
Thus, the critical points of the multivariable function are (0,√2), (0,-√2), and (5,0). Looks like your mistake was forgetting that -√2 works as a solution for y because squaring a negative number nets you a positive.
Hope this helped!