The equation for simple interest is:
A = P(1+rt);
A - final amount
P - initial, principal balance
r - annual interest rate
t = time in years.
A = 2000(1+.10*5) = 3000.
Ian R.
asked 04/07/23Bernie deposited
$
2,000
in an account earning 10% interest compounded annually.
To the nearest cent, how much will he have in 5 years?
The equation for simple interest is:
A = P(1+rt);
A - final amount
P - initial, principal balance
r - annual interest rate
t = time in years.
A = 2000(1+.10*5) = 3000.
Raymond B. answered 04/07/23
Math, microeconomics or criminal justice
A = 2,000(1+.10)^5
= 2000(1.1)^5
= $3,221.02
the general formula is
A=P(1+r/n)^nt
A= ending Amount
P=starting Position
r = annual rate of interest
n= number of compounding periods per year
t = time, in years
t=5, n=1, r=10% = .10
P=2000
had the problem asked for simple interest, instead of compounding
then there would have been 10% of 2000 = 200 per year
200 x 5 = 1000, so A=3000, but his problem requires
annual compounding so
A= 2000(1.1)^5
you need a calculator
or some tedious long hand multiplication
A=2000(1.1x1.1x1.1x1.1x1.1x1.1)
= 2000(1.61051)
= 3221.02
with simple interest, you only get interest on the original amount
with compounding interest, you get interest on the interest
in this case, it comes to exactly $3,221.02
no rounding is needed. that's the exact Amount, to the penny
had the problem asked for continous compounding
the formula would have become
A= Pe^rt = 2000e^(.10x5) = 2000e^.5 = 3297.44
that's useful as a rough check on the answer, as any compounding less than
continous will have an ending Amount less than for continous compounding
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