Please help me. thank you

Question

On common curves sketch the followings curves in two dimention:

i) the curve (x+3)²+y²=9

ii) the curve y=sqrt(9-(x+3)²).

Answer 1

The graph of (x - h)² + (y - k)² = r² is the circle with center (h,k) and radius r.

So, the graph of (x + 3)² + y² = 9 is the circle with center (-3,0) and radius 3.

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For the second problem, squaring both sides gives (x + 3)² + y² = 9, which is the circle descrid above.

Solving for y² and then taking square roots, gives y = √(9 - (x+3)²), which is the upper half of the circle with center (-3,0) and radius 3. (the lower half would be y = -√(9 - (x+3)²) )