Bradford T. answered 04/04/23
Retired Engineer / Upper level math instructor
Given: |Δx/x| = 0.01 |Δy/y| = 0.02 |Δz/z| = 0.03
w(x,y,z) = 8y2/(√x3√z2) = 8y2x-3/2z-1
∂w/∂x = 8(-3/2)y2x-5/2z-1
∂w/∂y = 16yx-3/2z-1
∂w/∂z = -8y2x-3/2z-2
dw(x,y,z) = ∂w/∂x dx + ∂w/∂y dy + ∂w/∂z dz
dw/w = (-3/2) dx/x + 2dy/y -dz/z after some algebra
= -3/2 (0.01) + 2(0.02) - (0.03) = -0.005
|Δw/w| = 0.005 = 0.5%