The graph of the function f(x)=ax^2+bx+c has its vertex at (0,3) and passes through the point (1,6). find a,b, and c

Question

a=

b=

c=

Answer 1

y=a(x-0)^2 +3 in vertex form

plug in (1,6) to find a

6=a(1^2)+3

a=3

b=0

c=3

y=3x^2 + 3