The hypotenuse of a right triangle is three times the length of one of the legs.

Question

The length of the other leg is 128‾‾‾‾√128 feet. Find the lengths of the leg and hypotenuse.

Answer 1

sides are 12, 4 and 8sqr2

= 12 for hypotenuse, 4 for one leg, and about 11.31

h = 3a

b = sqr128

h^2 = a^2 +b^2

9a^2 = a^2 + 128

8a^2 = 128

a^2 = 128/8 = 16

a = sqr16 = 4

h=3a=3(4) =12

sides are 12, 4 and sqr128=8sqr2= about 11.31