homework 10 mymathlab

Question

The number of cells in a tumor doubles every 3.5 months. If the tumor begins with a single​ cell, how many cells will there be after 2 ​years? after 3 ​years?

Answer 1

2= e^3.5r

ln2 =3.5r

f=ln2/3.5= about 19.8% rate of monthly growth

2 years = 24 months

T= e^.198(24)

= about 115.932629

=about 116 Tumor cells after 2 years

3 years =36 months

T=e^.198(36)

=about 1248.269982

about 1,248 Tumor cells after 3 years

24/3.5>6 or almost 7 doubling periods in 2 years

2^7= 128

24/3.5= about 6.857

2^6.857=115.92 = about 116

36/3.5>10 doubling periods

2^10=1,024

36/3.5=10.2857

2^10.2857= about 1248.26

=about 1,248