5/3x+1/3y=-4

-6x+5y+33

do I multiply the factions out by 3? then what?

5/3x+1/3y=-4

-6x+5y+33

do I multiply the factions out by 3? then what?

Tutors, sign in to answer this question.

Colby W. | Math and science tutorMath and science tutor

5/3x+1/3y=-4

-6x+5y+33

I'm assuming you are solving a system of linear equations and that you meant to write -6x+5y=33.

Multiplying by three could be a good idea. Fractions make things messy, so our system becomes:

5x + y = -12 && -6x + 5y = 33

Our goal is to eliminate one of the variables, solve for the other and plug that value into one of the equations to get the variable we eliminated. The easiest way I see to do that is to multiply the first equation by 5 and subtract from the second equation.

(-6x + 5y = 33)

- (25x + 5y = -60)

-31x = 93.

Solving for x, we get x = 93/(-31) = -3. Now we plug it back into one the equations (I choose 5x + y = -12 because it's simple) and we get 5(-3) + y = -12. Solve for y: y = -12 + 15 = 3. So both x is -3 and y is 3. You can check that (x, y) = (-3, 3) satisfies both of the original equations by direct substitution.

Already have an account? Log in

By signing up, I agree to Wyzant’s terms of use and privacy policy.

Or

To present the tutors that are the best fit for you, we’ll need your ZIP code.

Your Facebook email address is associated with a Wyzant tutor account. Please use a different email address to create a new student account.

Good news! It looks like you already have an account registered with the email address **you provided**.

It looks like this is your first time here. Welcome!

To present the tutors that are the best fit for you, we’ll need your ZIP code.

Please try again, our system had a problem processing your request.

Alexis G.

All-Subject/Test Prep Tutor, Specializing in Language Instruction

$11.25 per 15 min

View Profile >

Rebecca D.

Experienced and Patient Tutor for Math and Reading

$10.75 per 15 min

View Profile >

Eric T.

Mathematics is the language of the universe

$11.25 per 15 min

View Profile >