Raymond B. answered 03/17/23
Math, microeconomics or criminal justice
r(x) = x-5
s(x) =3x+5
(r+s)(x) = x-5+3x+5= 4x
(r-s)(x) = x-5-3x-5= -2x-10
r(s(x)) = r(3x+5) = 3x+5-5 = 3x
r(s(-2)) = 3(-2) = -6
s(-2) =3(-2)+5 = -1
r(s(-2))=r(-1) = -1-5 = -6
r(x)s(x)=(x-5)(3x+5)=3x^2 -10x-25
r(-2)s(-2)=3(-2)^2 -10(-2)--25=-12+20-25= 7
r(-2)=-2-5= -7
s(-2)=3(-2)+5=-1
r(-2)s(-2)=-7(-1)=7