Find the coefficient of x^2 in the expansion of [(1+2x)(3-x)]^5.

Answer 1

The way the question reads, you will need to FOIL (1 + 2X) (3 - X):

-2 x² + 5 x + 3

So, the set up after expanding the two binomials is:

[ -2 x² + 5 x + 3 ] ⁵

The coefficient is -2 for x².