Raymond B. answered 03/09/23
Math, microeconomics or criminal justice
$89 per day, for 320 room capacity
increase price by $1, 319 rooms are rented
for every one dollar increase one room less is rented
(320, 89) and (319,90) have a line through them with slope = -1
P =-(x-320) + 89
= -x + 320+89
= -x + 409
Revenue = Px= -x^2 + 409x
R' = -2x +409
Cost = C = 22x
C' = 22
R'-C' = -2x +409 -22
= -2x + 382
x = 382/2 = 191= revenue maximizing rooms rented
P = -(191-320) +89
= -(-129) +89
= 129 + 89
= 218
= $218 per room maximizes profits
Pearleen H.
Its saying the answer is wrong03/09/23