Raymond B. answered 03/08/23
Math, microeconomics or criminal justice
ax(x-1)(x+1)(x-5)
=ax(x^2-1)(x-5)
=ax(x^3 -5x^2 -x +5)
=a(x^4 -5x^3 -x^2 +5x)
to make the x^2 coefficient =6, a must = -6
=-6(x^4 -5x^3 -x^2 +5x)
P(x) = -6x^4 +30x^3 +6x^2 +30x has the given four zeros and required x^2 coefficient