Find the equation (in general form) of the bisector of the obtuse angle between the given lines:

Question

-12x + 5y + 3 = 0 and y = 5

Please include the solution so I can learn about it.

Answer 1

First equation,

-12x+5y+3=0........... (i)

Second equation,

-y+5=0....................... (ii)

a₁a₂+b₁b₂= positive then find the equation of line of bisector of obtuse angle,

(-12x+5y+3)/√((-12) ^2+(5) ^2)=(-y+5)/√((0) ^2+(-1) ^2)

(-12x+5y+3) /(13) =(-y+5)

(-12x) /13+(18y) /13-62/13=0