Raymond B. answered 03/08/23
Math, microeconomics or criminal justice
one boat leaves a dock at 2pm going due south at 5 kph
2nd boat goes due east at 10 kph and arrives at the same dock at 3pm
at what time were the two boats the closest, with minimum distance between them?
at 3pm they're 5 km apart
at 2pm 10 km apart
at 2:30 sqr(5^2+2.5^2)=sqr31.25 km apart
they're closest at 3pm, 1 hour after the 1st boat left the dock
60 minutes past 2 pm
Karolina R.
answer is wrong03/09/23