The length of a rectangle is 4 feet less than twice the width.what is the length of the rectangle if the perimeter is 102 feet

Answer 1

L=2w -4

P = 102 = 2L +2w

L+w = 102/2 = 51

2w-4 +w = 51

3w = 51+4 = 55

w = 55/3 = 18 1/3 feet = width of the rectangle

L = 51- 18 1/3 = 32 2/3 feet = Length of the rectangle

2L +2w = 36 2/3 + 65 1/3 = 102