3√(128m14n3) = [3√64 ] [3√2 ] [3√(m12) ][3√(m2) ][3√(n3) ]= 4m4n [3√(2m2)]
2 Answers By Expert Tutors
Raymond B. answered • 03/06/23
Tutor
5
(2)
Math, microeconomics or criminal justice
3rd root of 128m14n^3
= (128^(1/3))(m^(14/3))n
or if you want to round coefficients and exponents to nearest integer, then
= about 5nm5
there's only one real cube root, but also two imaginary roots
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