P(t)) = Po(1+r)^t
2029-2018= 11=t
P(11) = 7.6(1.02)^11
use a calculator
= 9.449644744 billion
= 9,449,644,744 in 2029
at 2% annual growth rate
when population was 7.6 billion in 2018
Ruby M.
asked 02/28/23The population of the world in 2018 was 7.6 billion and the annual growth rate was estimated at 2 percent per year. Assuming that the world population follows an exponential growth model Pt=P0(1+r)t, find the projected world population in 2029. (Round to the nearest tenth of a billion)
P(t)) = Po(1+r)^t
2029-2018= 11=t
P(11) = 7.6(1.02)^11
use a calculator
= 9.449644744 billion
= 9,449,644,744 in 2029
at 2% annual growth rate
when population was 7.6 billion in 2018
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