Inactive Tutor answered 02/28/23
17 ^2 = 289
h^2 = 17^2 + (h-1)^2
h^2 = 289 + h^2 -2h +1
0 = 290 -2h
h = 290/2 = 145
h-1 = 144
the other two sides are 144 and 145
hypotenuse = h = 145
longer leg = 144
145^2 = 17^2 + 144^2
21025 = 289 + 20736
Atreyu S.
asked 02/28/23The length of one of the legs of a right triangle is length17. the lengths of the other two are consecutive integers. Use Pythagorean theorem to solve for the smaller of the 2 missing sides (the second leg)
Inactive Tutor answered 02/28/23
17 ^2 = 289
h^2 = 17^2 + (h-1)^2
h^2 = 289 + h^2 -2h +1
0 = 290 -2h
h = 290/2 = 145
h-1 = 144
the other two sides are 144 and 145
hypotenuse = h = 145
longer leg = 144
145^2 = 17^2 + 144^2
21025 = 289 + 20736
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