one leg of a right triangle is 2 ft longer than the shorter side. if the length of the hypotenuse is 14 ft, how long is each leg (nearest tenth of a foot)

Question

one leg of a right triangle is 2 ft longer than the shorter side. if the length of the hypotenuse is 14 ft, how long is each leg (nearest tenth of a foot)

Answer 1

14^2 = s^2 + (s+2)^2

196 = s^2 + s^2 + 4s +4

2s^2 + 4s = 192

s^2 +2s = 96

s^2 +2s + 1 = 97

(s+1)^2 = 97

s+1 = sqr97

s = sqr97 - 1

s = about 9.8-1 = about 8.8 feet = shorter leg

s+2 = sqr97 + 1 = about 10.8 feet = Longer leg