
William W. answered 02/25/23
Top Pre-Calc Tutor
For a right circular cylinder V = πr2h therefore 50 = πr2h or, in our case where x = the radius then 50 = πx2h which means h = 50/(πx2)
When they talk about "4 cents per square inch to do trust the top and bottom, and 1 cent per square inch to construct the rest of the cylinder" they are talking about the surface area (SA).
For a right cylinder, the surface area is calculated form:
SA = 2πrh + 2πr2 or, in our case: SA = 2πxh + 2πx2
Plugging in "50/(πx2)" in place of "h" we get:
SA = 2πx(50/(πx2)) + 2πx2 = 100/x + 2πx2 therefore:
SA(x) = 100/x + 2πx2 where the first term is the surface area of the sides and the second term is the surface area of the top and bottom.
Since the cost is 4 cents for the top and bottom and 1 cent for the sides, then:
C(x) = (0.01)100/x + (0.04)2πx2
C(x) = 1/x + 0.08πx2
The minimum can be found by graphing this function and looking for the local minimum. (Using calculus, you can take the derivative and set it equal to zero but since this question is listed under pre-calc, I will assume you need to look at the graph)
The graph looks like this:
The minimum cost occurs when x (the radius) is 1.258 inches