Find the equation for the line that passes through the point (4,2) , and that is perpendicular to the line with the equation y=2/3x−1/3

Answer 1

the perp has slope = negative inverse of 2/3 = -3/2

tale 2/3, flip it upside down, and change its sign to get -3/2 which is the negative inverse

the perp equation is

y = -3x/2 +b

plug in the point (4,2) x=4, y=2 values to solve for b

2 =-3(4)/2 + b

b = 2 + 6 = 8

y =-3x/2 +8 is the perpendicular equation through the given point

that's in slope intercept form

or 2y =-3x +16

3x+2y = 16 in standard form