Raymond B. answered 02/22/23
Math, microeconomics or criminal justice
224= L+2w
224/2 by 224/4 =
112 by 56 ft
= max area = 112x56= 6272 ft^2
L=224-2w
A=Lw= 224w- 2w^2
A'= 224-4w=0
w=224/4 = 56 ft
L= 224-2(56)= 112 ft
Madisyn M.
asked 02/21/23A developer wants to enclose a rectangular grassy lot that borders a city street for parking. If the developer has
224
feet of fencing and does not fence the side along the street, what is the largest area that can be enclosed?
Raymond B. answered 02/22/23
Math, microeconomics or criminal justice
224= L+2w
224/2 by 224/4 =
112 by 56 ft
= max area = 112x56= 6272 ft^2
L=224-2w
A=Lw= 224w- 2w^2
A'= 224-4w=0
w=224/4 = 56 ft
L= 224-2(56)= 112 ft
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