Inactive Tutor answered 02/21/23
Tutor
New to Wyzant
x = sqr5
x^2 = 5
x^2-5 = 0
f(x) = (x-2)(x-3)(x^2-5)
= (x^2 -5x+6)(x^2 -5)
= x^4-5x^3 +x^2 +25x -30
Inactive Tutor answered 02/21/23
x = sqr5
x^2 = 5
x^2-5 = 0
f(x) = (x-2)(x-3)(x^2-5)
= (x^2 -5x+6)(x^2 -5)
= x^4-5x^3 +x^2 +25x -30
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.