Inactive Tutor answered 02/21/23
Tutor
New to Wyzant
x= 1+isqr3
x-1 = isqr3
x^2-2x + 1 = -3
x^2 -2x +4= 0
f(x)= (x+4)(x+5)(x^2-2x+4)
= (x^2 +9x +20)(x^2 -2x +4)
= x^4 +7x^3 +6x^2 -4x +80
Inactive Tutor answered 02/21/23
x= 1+isqr3
x-1 = isqr3
x^2-2x + 1 = -3
x^2 -2x +4= 0
f(x)= (x+4)(x+5)(x^2-2x+4)
= (x^2 +9x +20)(x^2 -2x +4)
= x^4 +7x^3 +6x^2 -4x +80
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