Inactive Tutor answered 02/21/23
Tutor
New to Wyzant
x= 1+2i
x-1 = 2i
x^2 -2x + 1= -4
x^2 -2x +5 = 0
f(x) = (x-3)(x^2 -2x +5)
f(x) = x^3 -5x^2 +11x -15
Inactive Tutor answered 02/21/23
x= 1+2i
x-1 = 2i
x^2 -2x + 1= -4
x^2 -2x +5 = 0
f(x) = (x-3)(x^2 -2x +5)
f(x) = x^3 -5x^2 +11x -15
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