What is the equation of the line that passes through the point ( 3 , 7 ) (3,7) and has a slope of 3?

Answer 1

I'd like to add another possible method.

The point-slope form of a non-vertical line is

y - y1 = m(x - x1), where m is the given slope and (x1, y1) is the given point.

Using (3, 7) as the point and 3 as the slope gives us

x1 = 3

y1 = 7

m = 3

Substituting all of these into the point-slope form we get

y - 7 = 3(x - 3)

[Something to note is that the opposite of each coordinate appears in the equation. For example the y-coordinate is 7, but it appears as -7 in the equation.]

The above is an equation for the line through (3, 7) with a slope of 3. If you want the equation in slope-intercept form,

1) distribute the 3 on the right side, and then

2) add 7 to both sides

y - 7 = 3x - 9

y = 3x - 2

Answer 2

In this question, I would simply answer by giving you the general equation of the line y = Ax + B

It has a slope of 3 so A should be equal to 3 so equation would be : y = 3x+ B.

Then, the line passes through the point (3,7) so equation becomes: 7 = 3*3 + B.

And, you will find B that is 7 - 3*3 = -2 so the result should be y = 3x - 2.

Hopefully, my support can help you well.